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11 April, 21:59

How much salt is in a mixture containing 10 gal of an 11% salt solution and 6 gal of a 7% salt solution

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  1. 11 April, 22:25
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    In a 10 gal of an 11% salt solution,

    11% of 10 gal are sal.

    11% * 10 gal = (11/100) * 10 gal = 0.11*10 gal = 0.1 gal is salt.

    Similarly, 0.07*6 gal = 0.42 gal is salt of the 6 gal in the second solution.

    The mixture is 10 gal + 6 gal = 16 gal, and contains a total of

    0.1 gal + 0.42 gal = 0.52 gal of salt.

    0.52 = x% of 16

    0.52=x%*16

    x = (0.52/16) * 100=0.0325*100=3.25

    Answer: there is 0.52 gal of salt in the mixture, that is 3.25%
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