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23 December, 06:47

If 2x^2 - 2y^2 = 72 and if x+y=18 what does x-y equal

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Answers (2)
  1. 23 December, 08:10
    0
    2x^2-2y^2=72

    divide both sides by 2

    x^2-y^2=36

    factor difference of 2 perfect squares

    (x-y) (x+y) = 36

    given that x+y=18, subsitute 18 for x+y

    (x-y) (18) = 36

    divide both sides by 18

    x-y=2
  2. 23 December, 09:53
    0
    First factor out the 2:

    x^2 - y^2 = 36

    x^2 - y^2 can be factored into (x+y) (y-y) so:

    (x + y) (x - y) = 36

    plug in your value:

    18 (x-y) = 36 and you should be able to take it from there
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