The length of a rectangle is 3 ft more than twice the width, and the area of the rectangle is 35 ft2. find the dimensions of the rectangle.

Hello:

let : y the length and : x the width ... x< y x > 0 and y > 0

y = 3+2x ... (1)

xy = 35 ... (2)

subsct in (2):

x (3+2x) = 35

2x² + 3x-35 = 0

delta : (3) ² - 4 (2) (-35) = 289 = 17²

x1 = (-3-17) / 4 < 0 (refused)

x2 = (-3+17) / 4 = 7/2

y = 3 + 2 (7/2) = 10