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11 July, 22:52

In developing an interval estimate for a population mean, a sample of 50 observations was used. the interval estimate was 19.76 ± 1.32. had the sample size been 200 instead of 50, the interval estimate would have been:

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  1. 11 July, 23:57
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    The formula for interval estimate would be: μ = M ± Z (sM)

    Where: μ is estimate

    M is the mean

    Z is the z value

    (sM) is the standard error

    μ = M ± Z (sM)

    n = 200 rather than 50 (√200 = 2√50)

    ⇒ ME = (1/2) * 1.32 =.66

    Using the formula above, plugging this in will give us: μ = 19.76 ±.66

    = 19.76 ±.66 is the confidence interval or interval estimate
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