You can represent an odd integer whith the expression 2n+1, where n is any integer. Write and solve an equation to find three consecutive odd that have a sum of 63

Any odd number can be expressed by 2n+1.

For example,

2n+1=111

2n=110

n=110/2=55

means that 111 is 2n+1 for n=55

Thus if an odd number is 2a+1, the next few numbers are as follows:

2a+1, 2a+2, 2a+3, 2a+4, 2a+5

So 2a+1, 2a+3 and 2a+5 are 3 consecutive odd numbers.

Back to our problem:

three consecutive odd numbers whose sum is 63 are:

(2n+1) + (2n+3) + (2n+5) = 63

6n+9=63

6n=63-9=54

n=54/6=9

2n+1=2*9+1=18+1=19, the 2 next odd numbers are 21 and 23

Answer: 19, 21, 23