Solve the system of equations using the linear combination method.

{5m+3n=41

3m-6n=9

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m =

n =

Solve the system of equations using the linear combination method.

{6g+8h=40

-6g+2h=-20

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g =

h =

Solve the system of equations using the linear combination method.

{9x+5y=35

2x+5y=0

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x =

y =

1. 5m+3n=41

3m-6n=9 (multiplying the first equation by 3 and the second by 5), we get;

15m+9n=123

15m-30n = 45 (subtracting the two equations)

39n = 78

n = 2, and

to get m we substitute n with 2

3m = 9+6 (2)

3m = 21

m = 7

Therefore, n=2 and m=7

2. 6g + 8h=40

-6g + 2h = - 20 (Adding the two equations to eliminate g)

10 h = 20

h = 2

to get g we substitute h with two

6g = 40 - 8 (2)

= 24

g = 4

Therefore, g = 4 and h = 2

3. 9x + 5y = 35

2x + 5y = 0 (subtracting the two equations to eliminate y)

7x = 35

x = 5

To get y we substitute x with 5

5y=35-9 (5)

5y = - 10

y = - 2

Therefore, x=5 and y=-2