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23 April, 00:35

The sum of two integers is thirty. Eight times the smaller integer is 6 more than 5 times the larger interger. Find the integers

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  1. 23 April, 03:11
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    First of all you must form equations. Now,

    Let the smaller integer = x and

    Let the greater integer = y

    x + y = 30 ... (1) Given. The sum of the integers

    8x = 5y + 6 or } Given. 8 times the smaller integer is

    8x - 5y = 6 ... (2) } bigger by 6 than 5 times the greater

    } integer.

    (1) * 5, we get,

    5x + 5y = 150 ... (3)

    By adding Eq. (2) and (3),

    13x = 156

    So x = 156/13 = 12

    By replacing this value of x in Eq. (1), we get

    12 + y = 30

    So y = 30 - 12 = 18

    So, 12 and 18 are the integers.
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