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29 April, 11:02

At sea, the distance D to the horizon is directly proportional to the square root of the elevation E of the observer. If a person who is 36 feet above the water can see 7.4 miles, find how far a person 49 feet above the water can see.

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  1. 29 April, 11:29
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    The problem says that the distance D to the horizon is directly proportional to the square root of the elevation E of the observer, so:

    The person who is 36 feet above the water ⇒ √36=6

    A person 49 feet above the water ⇒ √49=7

    So, by proportions, you have:

    (7/6) x7.4 = 8.63 miles

    Therefore, the answer is: a person 49 feet above the water can see 8.63 miles
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