Determine the amounts of 20% and 50% salt solutions that should be mixed to obtain 300 gallons of 41% salt solution.

Will give brainliest to best answer

Question

Mathematics

Mckinley Mcgee

9 October, 00:40

Determine the amounts of 20% and 50% salt solutions that should be mixed to obtain 300 gallons of 41% salt solution.

Will give brainliest to best answer

+2

Answers (1)

Know the Answer?

Alicia Blevins · Answer 1

Assume that solution with 20% and 50% salt is x and y gallons respectively.

Therefore,

x+y = 300 = > y=300-x

Additionally

20x+50y = 300*41 = 12300

Substituting for y

20x+50 (300-x) = 12300 = > 20x+15000-50x = 123000 = > - 30x = - 2700

x = 90 gallons

y = 300-x = 300 - 90 = 210 gallons

Determine the amounts of 20% and 50% salt solutions that should be mixed to obtain 300 gallons of 41% salt solution.Will give brainliest to best answer

Determine the amounts of 20% and 50% salt solutions that should be mixed to obtain 300 gallons of 41% salt solution.

Will give brainliest to best answer