The perimeter of a rectangle is 132 feet and its area is 1080 square feet. find the dimensions

2x + 2y=132

xy=1080

Let x=1080/y

2160/y + 2y=132

2y^2 - 132y + 2160=0

2 (y^2-66y+1080) = 0

2 (y-30) (y-33) = 0

y=30 or y=33

(36,30) or (30,36)

So ... x=30,36 and y=36,30. Either way, the answer is 30 by 36 or 36 by 30.