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10 January, 00:12

What are the solutions of the equation x^4-5x-^2-14=0

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  1. 10 January, 00:27
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    So you want to start to factor so you get (x²+2) (x²-7) = 0. Now set each () to 0, so you get (x²+2) = 0 and (x²-7) = 0. The first ends with + √2i and - √2i, the second ends with + √7 and - √7
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