The perimeter of a rectangle is 68 ft. The ratio of the length to the width is 9 : 8. What are the dimensions of the rectangle?

Perimeter of a rectangle=2 (length) + 2 (width)

length=x

width=y

We can suggest the following system of equations:

2x+2y=68

x/y=9/8

We solve this system of equations by substitution method.

2x+2y=68 ⇒x+y=34 ⇒y=34-x

x / (34-x) = 9/8

8x=9 (34-x)

8x=306-9x

8x+9x=306

17x=306

x=306/17

x=18

y=34-x

y=34-18

y=16

dimensions of a rectanctle=length x width

dimensions of a rectangle=18 x 16

Answer: the dimensions of this rectangle will be 18 x 16 (ft)