The ages of three friends are consecutively one year apart. Together their ages total 48 years. Which equation can be used to find the age of each friend (where a represents the age of the youngest friend) ?

A. 3a=48

B. a (a+1) (a+2) = 48

C. a + (a-1) + (a-2) = 48

D. a + (a+1) + (a+2) = 48

Question

Mathematics

Emerson Molina

1 July, 08:08

The ages of three friends are consecutively one year apart. Together their ages total 48 years. Which equation can be used to find the age of each friend (where a represents the age of the youngest friend) ?

A. 3a=48

B. a (a+1) (a+2) = 48

C. a + (a-1) + (a-2) = 48

D. a + (a+1) + (a+2) = 48

+1

Answers (2)

Know the Answer?

Kassidy · Answer 1

Three consecutive numbers ... a, a + 1, a + 2

together their ages total 48 years

a + (a + 1) + (a + 2) = 48 < = = ur equation

3a + 3 = 48

3a = 48 - 3

3a = 45

a = 45/3

a = 15

a + 1 = 15 + 1 = 16

a + 2 = 15 + 2 = 17

so their ages are : 15,16,17

Imani Martin · Answer 2

D. a + (a + 1) + (a + 2) = 48

The ages of the friends are 15, 16, and 17

The ages of three friends are consecutively one year apart. Together their ages total 48 years. Which equation can be used to find the age of each friend (where a represents the age of the youngest friend) ?A. 3a=48B. a (a+1) (a+2) = 48C. a + (a-1) + (a-2) = 48D. a + (a+1) + (a+2) = 48

The ages of three friends are consecutively one year apart. Together their ages total 48 years. Which equation can be used to find the age of each friend (where a represents the age of the youngest friend) ?

A. 3a=48

B. a (a+1) (a+2) = 48

C. a + (a-1) + (a-2) = 48

D. a + (a+1) + (a+2) = 48