Suppose tom has 22 coins totaling $3.70. if he has only dimes and quarters, how many of each type does he have?

The first thing we must do for this case is to define variables:

x: dimes

y: quarters

We now write the system of equations.

We have then:

x + y = 22

0.10x + 0.25y = 3.70

Solving the system of equations we have:

x = 12

y = 10

Answer:

He has:

12 dimes

10 quarters