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24 March, 16:52

First, we need to find the radius: r = sqrt ((-3) ^2 + 1^2) = sqrt (10) sin (theta) = y/r = 1/sqrt (10) = sqrt (10) / 10 cos (theta) = x/r = - 3/sqrt (10) = - 3sqrt (10) / 10 tan (theta) = y/x = - 1/3

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  1. 24 March, 18:37
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    r = sqrt (10) = sqrt (10) sin (0) = y/r = 1/sqrt (10) = (cos (0)) / sqrt (10) = x/r = - 3/sqrt (10) = - (3 tan (0)) / sqrt (10) = y/x = - 1/3.
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