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26 January, 19:00

Find the equation of a parabola with vertex (2, - 1), opens upward and has focal width of 16.

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  1. 26 January, 22:50
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    The equation of the parabola is given by:

    y=a (x-h) ^2+k

    where:

    (h, k) is the vertex:

    thus we shall have:

    y=16 (x-2) ^2-1

    Expanding the above we get:

    y=16 (x^2-2x+4) - 1

    y=16x^2-32x+63
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