In a certain section of southern california, the distribution of monthly rent for a one-bedroom apartment has a mean of $2,200 and a standard deviation of $250. the distribution of the monthly rent does not follow the normal distribution. in fact, it is positively skewed. what is the probability of selecting a sample of 50 one-bedroom apartments and finding the mean to be at least $1,950 per month? (round z value to 2 decimal places and final answer to 4 decimal places.)

Question

Mathematics

Oconnell

28 September, 02:33

In a certain section of southern california, the distribution of monthly rent for a one-bedroom apartment has a mean of $2,200 and a standard deviation of $250. the distribution of the monthly rent does not follow the normal distribution. in fact, it is positively skewed. what is the probability of selecting a sample of 50 one-bedroom apartments and finding the mean to be at least $1,950 per month? (round z value to 2 decimal places and final answer to 4 decimal places.)

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Selena · Answer 1

The distribution of will still use a normal distribution though the distribution is positively skewed.

Mean μ = 2200

Standard deviation σ = 250

Standard error σ / √ n = 250 / √ 50 = 35.36

standardize xbar to z = (xbar - μ) / (σ / √ n)

P (xbar > 1,950) = P (z > (1,950-2200) / 35.36)

= P (z > - 7.07) = 1

So probability is 1 or virtually certain.