Find the equation of a line that passes through (-3,10) and is perpendicular to y = 3.

a) y = 10

b) y = 3x + 19

c) x = - 3

d) y = - 3x + 9

Question

Mathematics

Shelby Archer

29 November, 01:44

Find the equation of a line that passes through (-3,10) and is perpendicular to y = 3.

a) y = 10

b) y = 3x + 19

c) x = - 3

d) y = - 3x + 9

+5

Answers (2)

Know the Answer?

Thaddeus Cameron · Answer 1

Thaddeus Cameron 29 November, 02:01

0

C because Im just guessing

Romeo Hicks · Answer 2

Y=3 is a horizontal line. So, a line perpendicular to y=3 must be vertical. The only vertical line among the choices is x=-3, so C must be the answer.

Find the equation of a line that passes through (-3,10) and is perpendicular to y = 3.a) y = 10b) y = 3x + 19c) x = - 3d) y = - 3x + 9

Find the equation of a line that passes through (-3,10) and is perpendicular to y = 3.

a) y = 10

b) y = 3x + 19

c) x = - 3

d) y = - 3x + 9