What is the missing constant term in the perfect square that starts with x^2+6xx 2 + 6xx, start superscript, 2, end superscript, plus, 6, x?

For this case we have the following polynomial:

x ^ 2 + 6x

The missing value to complete the square is given by:

x ^ 2 + 6x + (6/2) ^ 2

Rewriting we have:

x ^ 2 + 6x + (3) ^ 2

x ^ 2 + 6x + 9

Then, completing the square we have:

(x + 3) ^ 2

Answer:

the missing constant term in the perfect square is:

9