You are given the expression 4-16 = (2-4) (2+4). Which polynomial identity describes the above numerical relationship?

A). n^2+4^2 = (n-4) (n+4)

B). n^2-4^2 = (n-4) (n+4)

C).4^2+n^2 = (2+n) (4-n+n^2)

D).2^2-n^2 = (4-n) (4+n)

In order to factorize this, we will use the distributive property which means to multiply each of the terms in the next factor.

So, (2x2) + (2x4) + (-4x2) + (-4x4)

4+8-8-16=-12

As we can see, that the two 8s cancel each other leaving us with 4-16

Response B best resembles this relationship. If we use the distributive property here, we get (nxn) + 4n-4n-16

Leaving us with, n^2-16

To check, we can substitute n for 2 and check if we get - 12