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26 September, 10:27

The position of an object at time t is given by s (t). Find the instantaneous velocity at the indicated value of t.

s (t) = 4at^2 + 7 at t = 4

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Answers (2)
  1. 26 September, 11:31
    0
    S (t) = 4at^2 + 7

    s' (t) = v = 8at

    so velocity at t = 4 = 8a*4 = 32a
  2. 26 September, 14:00
    0
    If the position is given by s (t) = 4at^2 + 7

    (by which I assume you mean s (t) = 4*a*t^2 + 7)

    then the velocity is given by the derivative ds/dt, which is 4*a*2*t.

    Now let t = 4: (ds/dt) (4) = 4*a*2^4 = 4*a*16 = 64a (answer)
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