2. The sum of two integers is 74. The larger is 26 more than twice the smaller. Find the two integers.

74=x+y is the equation at the beginning we will say that x is the smaller number and y is the larger one. Now we substitute the larger number (y) for 26+2x. Plug that into the beginning equation to get 74 = x + 26+2x. Now solve.

74=3x+26

48=3x

16=x

So we know that our smaller number is 16. To find the larger number we plug the value of the smaller number into the equation for the larger number like this.

y=26+2x

y=26+2 (16)

y=26+32

y=58.

So to check our answer we can plug in both values into the beginning equation.

74=58+16

74=74.

So to sum this up the smaller number is 16 and the larger number is 58.