Which values of x will make the expression 6x^2-54/5x^2-20 equal to 0? Check all that apply.

-9

-3

-2

0

2

3

9

From the given expression:

(6x^2-54) / (5x^2-20)

simplifying the above we get:

[6 (x^2-9) ]/[5 (x^2-4) ]

=[6 (x-3) (x+3) ]/[5 (x+2) (x-2) ]

The expression will be 0 when the numerator is zero, thus given the numerator, the values that will make it 0 will be x=3 and x=-3

hence the answer is:

x=-3 and x=3