A triangle has the vertices: A (-4,7), B (-3, 5) and C (8, - 1).

What is the length of the perimeter of the triangle?

You can find the length of the sides using the a result of the Pythagorean Theorem. Each side is:

s^2 = (x2-x1) ^2 + (y2-y1) ^2 so you have:

s1^2 = (-3--4) ^2 + (5-7) ^2

s1^2=1+4

s1=√5

s2^2 = (8--3) ^2 + (-1-5) ^2

s2^2=121+36

s2=√157

s3^2 = (8--4) ^2 + (-1-7) ^2

s3^2=144+64

s3=√208

The perimeter is:

p=s1+s2+s3

p=√5+√157+√208 units

p≈29.19 units (to nearest hundredth)