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17 October, 06:48

Problem page the length of a rectangle is 6 cm longer than its width. if the perimeter of the rectangle is 40 cm, find its area.

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  1. 17 October, 10:09
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    P = 2 (L + W)

    P = 40

    L = W + 6

    40 = 2 (W + 6 + W)

    40 = 2 (2W + 6)

    40 = 4W + 12

    40 - 12 = 4W

    28 = 4W

    28/4 = W

    7 = W ... so the width is 7 cm

    L = W + 6

    L = 7 + 6

    L = 13 ... and the length is 13 cm

    the area is the length times the width

    A = L * W

    A = 13 * 7

    A = 91 cm^2 <===
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