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20 November, 16:32

Find the solution of 3 times the square root of the quantity of x plus 6 equals negative 12, and determine if it is an extraneous solution.

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  1. 20 November, 20:00
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    3 sqrt (x + 6) = - 12

    xqrt (x + 6) = - 4

    x + 6 = 16

    x = 10

    Substituting for x in the original equation:-

    3 sqrt (10+6) = 3*sqrt16 = 3 * - 4 = - 12

    not extraneous
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