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23 May, 18:23

An archery target is shown. The length of a side of the Inner square is 4 m and the length of a side of the outer square is 7 m If an arrow hits the target at random, what Is the probability that it hits the inner square? Round to the nearest percent.

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  1. 23 May, 21:46
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    This is the concept of the probability and statistics. To get the probability of hitting the inner circle we proceed as follows;

    P (inner square) = [area of inner circle]/[area of outer square]

    area of inner square will be:

    Area=length*width

    Area=4*4=16 m^2

    Area of outer square:

    Area=7*7=49 m^2

    thus;

    P (hitting inner square) = 16/49=0.3265=32.65%
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