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9 December, 02:11

When you solve the equation x^3-3x^2+2x=0, how many roots are greater than 1/2?

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  1. 9 December, 04:20
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    Hello:

    x^3-3x^2+2x=0

    x (x²-3x+2) = 0

    x (x-1) (x-2) = 0

    x = 0 or x-1 = 0 or x-2 = 0

    x = 0 or x = 1 or x = 2

    two roots are greater than 1/2 : 1 and 2
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