Ask Question
28 June, 17:16

The probability of contamination in batch 1 of a drug (event A) is 0.16, and the probability of contamination in batch 2 of the drug (event B) is 0.09. The probability of contamination in batch 2, given that there was a contamination in batch 1, is 0.12. Given this information, which statement is true? Events A and B are independent because P (B|A) = P (A). Events A and B are independent because P (A|B) ≠ P (A). Events A and B are not independent because P (B|A) ≠ P (B). Events A and B are not independent because P (A|B) = P (A). NextReset

+2
Answers (1)
  1. 28 June, 19:41
    0
    We have:

    P (A) = 0.16

    P (B) = 0.09

    If event A and event B are independent, then P (A) * P (B) = P (A∩B)

    So, P (A∩B) should be 0.16 * 0.09 = 0.0144 if event A and event B are independent.

    But we also have another probability related to event A and event B in our case, the conditional probability P (B|A) ⇒ Read, the probability of event B happening given event A is happening. The conditional probability P (B|A) is given by P (A∩B) : P (A). We know the value of P (B|A) and P (A), so we can work out the value of P (A∩B) = P (B|A) * P (A) = 0.12 * 0.16 = 0.0192. This value of P (A∩B) is not as expected if event A and event B were independent.

    We need the value of P (B) to be equal to P (B|A) in order for the two events to be independent

    Answer: Events A and B are not independent because P (B|A) ≠ P (B)
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “The probability of contamination in batch 1 of a drug (event A) is 0.16, and the probability of contamination in batch 2 of the drug (event ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers