Ask Question
14 November, 04:58

There are 15 cherry, 17 grape, and 14 orange juice boxes in the cooler. What is the probability of randomly selecting a cherry then selecting a grape without replacement?

Question 3 options:

17/138

119/1058

136/1035

29/46

+2
Answers (2)
  1. 14 November, 06:04
    0
    15 cherry, 17 grape, and 14 orange ... total of 46 juice boxes

    P (cherry) = 15/46

    without replacing

    P (grape) = 17/45 (I put it over 45 because since the 1st was not replaced, we have 1 less juice box)

    P (both events happening) = 15/46 * 17/45 = 17/138 <==
  2. 14 November, 07:17
    0
    15 + 17 + 14 = 46 juice boxes total

    15 cherry = 15/46

    17 grape = 17/45

    15/46 * 17/45 = 17/138
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “There are 15 cherry, 17 grape, and 14 orange juice boxes in the cooler. What is the probability of randomly selecting a cherry then ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers