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11 January, 20:45

The length of a rectangle is twice its width. if the area of the rectangle is 200 yd2, find its perimeter.

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  1. 11 January, 22:40
    0
    Width: x

    Length: 2x

    Area=x (2x) = 2x^2

    2x^2=200

    x^2=100

    x=10 or - 10 (reject as x>0) [width cannot be less than 0, doesnt make sense]

    Perimeter

    =x+x+2x+2x

    =6x

    =6 (10)

    =60 yd
  2. 11 January, 23:31
    0
    The answer to this question is 60yd
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