An article reported that for a sample of 41 kitchens with gas cooking appliances monitored during a one-week period, the sample mean co2 level (ppm) was 654.16, and the sample standard deviation was 165.74. (a) calculate and interpret a 95% (two-sided) confidence interval for true average co2 level in the population of all homes from which the sample was selected. (round your answers to two decimal places.)

Question

Mathematics

Madilyn Gonzalez

29 July, 15:56

An article reported that for a sample of 41 kitchens with gas cooking appliances monitored during a one-week period, the sample mean co2 level (ppm) was 654.16, and the sample standard deviation was 165.74. (a) calculate and interpret a 95% (two-sided) confidence interval for true average co2 level in the population of all homes from which the sample was selected. (round your answers to two decimal places.)

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Marlie Macias · Answer 1

Given:

Mean of 654.16

Sample size is 41

Standard dev is 165.74

Alpha is 1 - 0.95, Z (0.025) = 1.96

So the computation would be:

Mean ± Z * s/sqrt (n)

= 654.16 ± 1.96*165.74/sqrt (41)

= 654.16 ± 1.96*25.88

= 654.16 ± 50.7248

= 603.4352, 704.8848 is the confidence interval

Interpretation: We are 95% confident that this confidence interval contains the true pop. mean