Mathematics

Harper Walls

3 November, 18:45

Select from the drop-down menus to correctly complete the proof.

To prove that 3√⋅12 is irrational, assume the product is rational and set it equal to ab , where b is not equal to 0. Isolating the radical gives 3√=2ab. The right side of the equation is (irrational, rational). Because the left side of the equation is (irrational, rational), this is a contradiction. Therefore, the assumption is wrong, and the product is (irrational, rational).