Adam had RM40. Susan gave 1 over 3 of her money to Adam. After giving 1 over 8 of his money to Gopal, Adam still had RM350. Find the total amount Susan had originally

Adam had: RM40.

Susan had x money but she gave 1/3 of her money to Adam: x-1/3x+40=y

y-Adam's money after Susan gave his 1/3 of her's money.

After giving 1/8 of his money to Gopal, Adam still had RM350: y-1/8y=350

x-1/3x+40=y

y-1/8y=350⇒7/8y=350⇒y=400

2/3x+40=400⇒2/3x=360⇒x=540

Originally Susan had RM540.

Let x = Susan's money originally

Let y = Adam's money before giving to Gopal

From Adam and Susan's transaction:

y = 40 + (1/3) x

From Adam and Gopal's transaction:

350 = (7/8) y

y = 400

Adam has RM400 before giving to Gopal.

400 = 40 + (1/3) x

x = 1080

Therefore, Susan had RM1080 originally.