How much material is needed to construct a triangular tent that is 24 feet wide, 5 feet tall, and 20 feet long with side measurements of 13 feet?

816 square feet

1024 square feet

1120 square feet

1392 square feet

The answer is " 1120 square feet. ".

Total surface area of a triangular prism = width x height + (sum of sides + width) x length and here;

width = 24

height = 5

sides = 13

length = 20

= (24 x 5) + (13 + 13 + 24) x 20

= 120 + (50 x 20)

= 120 + 1000

= 1120 square feet.