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13 April, 05:36

A ball is thrown from a height of 80 feet with an initial downward velocity of 4/fts. The ball's height h (in feet) after t seconds is given by the following.

h-80-4t-16t^2

How long after the ball is thrown does it hit the ground? Round your answer (s) to the nearest hundredth.

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  1. 13 April, 07:30
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    Alright, so we have h=80-4t-16t^2. We have to find when h=0. We can use the quadratic formula!

    (use x as t)

    x = (4+-sqrt (16 - (-64*80)) / 32 = (4+-sqrt (5136)) / 32, and since 4-sqrt (5136) is clearly negative that doesn't work, so we have (4+sqrt (5136)) / 32, which is approximately 2.36
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