A regulation tennis court for a double match is laid out so that it's length is 6 ft more than two times its width. the area of a doubles court is 2808 square feet what is the length and width of the singles Court

Area=LW

L=6+2W

given

A=2808

subsitute

2808=LW

subsitute 6+2W for L

2808 = (6+2W) (W)

2808=2W²+6W

divide both sides by 2

1404=W²+3W

minus 1404 from both sides

0=W+3W-1404

farctor, what 2 numbers multiply to get - 1404 and add to get 3

-36 and 39

0 = (W-36) (W+39)

set each to zero

0=W-36

36=W

0=W+39

-39=W

false, can't have negative dimentions

W=36

L=6+2W

L=6+2 (36)

L=6+72

L=78

the length is 78ft

the width is 36ft

0=