g (x) = x3 + 6x2 + 12x + 8 Determine the function's value when x = - 1. g (-1) = - 3 g (-1) = 0 g (-1) = 1 g (-1) = 27

Question

Mathematics

Janiah Smith

15 December, 07:48

g (x) = x3 + 6x2 + 12x + 8 Determine the function's value when x = - 1. g (-1) = - 3 g (-1) = 0 g (-1) = 1 g (-1) = 27

+1

Answers (1)

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Aracely Duffy · Answer 1

The correct answer is that g (-1) = 1.

To do this problem, we have to plug in - 1 for x and evaluate the expression.

g (-1) = x^3 + 6x^2 + 12x + 8

(-1) ^3 + 6 (-1) ^2 + 12 (-1) + 8

-1 + 6 - 12 + 8

1