Given: ΔАВС, m∠ACB = 90° CD ⊥ AB, m∠ACD = 60° BC = 6 cm Find CD, Area of ΔABC

Question

Mathematics

Nathanial

22 January, 21:57

Given: ΔАВС, m∠ACB = 90° CD ⊥ AB, m∠ACD = 60° BC = 6 cm Find CD, Area of ΔABC

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Answers (1)

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Rich · Answer 1

Area=1/2*base*height

given that ABC is right angled triangle, the height will be given by:

tan theta=opposite/adjacent

tan 60=h/6

h=6tan60

=10.4

thus the area will be:

A=1/2x6x10.4

=31.2 cm^2