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22 January, 21:57

Given: ΔАВС, m∠ACB = 90° CD ⊥ AB, m∠ACD = 60° BC = 6 cm Find CD, Area of ΔABC

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  1. 23 January, 01:19
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    Area=1/2*base*height

    given that ABC is right angled triangle, the height will be given by:

    tan theta=opposite/adjacent

    tan 60=h/6

    h=6tan60

    =10.4

    thus the area will be:

    A=1/2x6x10.4

    =31.2 cm^2
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