5). What was the value of 1/2^-2 x^-3 y^5 for x=2 & y = - 4

A) 16

B) - 4

C) - 1/32

D) - 16

Question

Mathematics

Deja

6 April, 20:50

5). What was the value of 1/2^-2 x^-3 y^5 for x=2 & y = - 4

A) 16

B) - 4

C) - 1/32

D) - 16

+1

Answers (1)

Know the Answer?

Andres · Answer 1

The value of the expression is given by:

(1/2) ^-2x^-3y^5

substituting x=-4 and y=2 we get:

(1/2) ^-2 (-4) ^-3 (2) ^5

=2^5 / ((1/2) ² * (-4) ³)

=-2

5). What was the value of 1/2^-2 x^-3 y^5 for x=2 & y = - 4A) 16B) - 4C) - 1/32D) - 16

5). What was the value of 1/2^-2 x^-3 y^5 for x=2 & y = - 4

A) 16

B) - 4

C) - 1/32

D) - 16