The equation h (t) = - 16t^2 + 19t + 110 gives the height of a rock, in feet, t seconds after it is thrown from a cliff.

What is the initial velocity when the rock is thrown?

The initial velocity is 19 ft/s.

This equation is in the form

h (t) = - 16t²+v₀t+h₀, where - 16 is the gravitational constant, v₀ is the initial velocity, and h₀ is the initial height.

Our equation is h (t) = - 16t²+19t+110. In this equation, the number in place of v₀ is 19, so the initial velocity is 19.