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22 June, 00:07

Use the remainder theorem to determine which number is a root of f (x) = 3x3 + 6x2 - 26x - 8. A) - 4 B) - 2 C) 2 D) 4

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  1. 22 June, 01:52
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    Given that the function is given by:

    f (x) = 3x^3+6x^2-26x-8

    To determine which number is a root we substitute the value in the equation, the value of x that we result in the function being a zero is the root of the equation.

    First plugging in x=-4 in the expression gives us:

    f (-4) = 3 (-4) ^3+6 (-4) ^2-26 (-4) - 8

    f (-4) = 3 (-64) + 6 (16) + 104-8

    simplifying the above we get:

    f (-4) = 0

    This implies that x=-4 is a root of the function

    thus the answer is:

    A] - 4
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