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17 April, 09:57

I am trying to figure out how to write the equation to solve: the first number is 5 less than the second number. Four times the first number plus 5 times the second number is 74. Find the numbers

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  1. 17 April, 13:22
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    There are two numbers involved, let's call them x and y (x=first y=second).

    Let's look at the information involved.

    The first number is 5 less than the second.

    So, X=Y-5.

    Four times the first number plus 5 times the second number is 74.

    So we can deal with just one variable, which will be Y, we can insert the expression y-5 for x.

    So, the equation would look like:

    4 (y-5) + 5Y=74

    Let's solve.

    We need to multiply the parenthesis first.

    4y-20+5Y=74

    Now add like terms.

    9Y-20=74

    We need Y by itself, so lets add 20 to both sides.

    9Y=94

    Let's divide.

    10 4/9=Y

    Since the first number is five less, it is 5 4/9. Let's check by putting it through the equation.

    4 (5 4/9) + 5 (10 4/9) =

    21 7/9+52 2/9

    73+1=74

    So the numbers are 5 4/9 and 10 4/9.
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