Ask Question
25 July, 19:51

Find algebraically the zeros for p (x) = x^3+x^2-4x-4

+3
Answers (1)
  1. 25 July, 20:06
    0
    One zero is - 1

    because p (-1) = (-1) ^3 + (-1) ^2 - 4 (-1) - 4 = 0

    So one factor of p (x) is x + 1

    Dividing p (x) by x + 1 gives the quotient

    x^2 - 4

    x - 2) (x + 2) = 0

    x = 2, - 2

    The zeroes are - 2,-1 and 2
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Find algebraically the zeros for p (x) = x^3+x^2-4x-4 ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers