Ask Question
9 March, 17:19

An object in shm oscillates with a period of 4.0s and an amplitude of 11 cm. part a how long does the object take to move from x = 0.0 cm to x = 6.5 cm.

+4
Answers (1)
  1. 9 March, 18:24
    0
    If the Amplitud is 11*2=22cm and the wave was in shm then we can get the wavelength as 11*2=22s.

    From the wave equation,

    v=fλ Where v⇒speed

    f⇒frequency and

    λ⇒Wavelength

    And we know that;

    f=1/T

    f = 1/4 = 0.25 Hz

    ∴v = 0.25 * 22 = 5.5 cm/s

    Since we know know the speed of the object we can get its time it takes from (0-6.5) cm.

    v = fλ = λ/T

    ∴T = λ/v

    = 6.5/5.5

    = 1 2/11

    = 1.181818s

    The time taken for the object to move from x = 0.0 cm to x = 6.5 cm is 1.181818s
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “An object in shm oscillates with a period of 4.0s and an amplitude of 11 cm. part a how long does the object take to move from x = 0.0 cm ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers