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12 February, 18:47

How to find the maximum height projectile motion?

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  1. 12 February, 19:49
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    Y=v (initial) * t+1/2at^2

    since the velocity is zero at the maximum height then we get

    y=1/2at^2

    a is just acceleration due to gravity so a=g which is 9.8 m/s^2.

    so y=1/2gt^2.
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