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9 April, 09:20

If x is normally distributed random variable with a mean of 8.20 and variance of 4.41, and that p (x >

b. =.08, then the value of b is:

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Answers (1)
  1. 9 April, 12:46
    0
    Given that mean is 8.20 and variance is 4.41, the value of b will be calculated as follows:

    P (x>b) = 0.08

    ⇒P (x
    the z-score corresponding to this probability is:

    z=1.41

    but the formula for z-score is given by:

    z = (x-μ) / σ

    where:

    μ=mean

    σ=standard deviation

    thus plugging in the values we obtain:

    1.41 = (x-8.2) / √4.41

    1.41 = (x-8.2) / 2.1

    solving for x

    1.41*2.1=x-8.2

    x=2.961+8.2

    x=11.161

    Hence the answer is x=11.161
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