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4 September, 20:35

What is an equation of a parabola with a vertex at the origin and directrix x=4.75?

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  1. 4 September, 23:54
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    An equation for the parabola would be y²=-19x.

    Since we have x=4.75 for the directrix, this tells us that the parabola's axis of symmetry runs parallel to the x-axis. This means we will use the standard form

    (y-k) ²=4p (x-h), where (h, k) is the vertex, (h+p, k) is the focus and x=h-p is the directrix.

    Beginning with the directrix:

    x=h-p=4.75

    h-p=4.75

    Since the vertex is at (0, 0), this means h=0 and k=0:

    0-p=4.75

    -p=4.75

    p=-4.75

    Substituting this into the standard form as well as our values for h and k we have:

    (y-0) ²=4 (-4.75) (x-0)

    y²=-19x
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