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19 June, 08:50

Find the 32nd term of the sequence 34, 37, 40, 43

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Answers (2)
  1. 19 June, 10:31
    0
    The answer would be 127 the pattern is + 3
  2. 19 June, 11:48
    0
    Increases by 3 each time

    aritmetic sequence, firsrt term is 34, 3=common differnce

    an=a1+d (n-1) is da formlua

    a1=first term

    d=common differnce

    an=34+3 (n-1)

    so 32n'd term is

    a32=34+3 (32-1)

    a32=34+3 (31)

    a32=34+93

    a32=127

    the 32nd term is 127
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