Find the 32nd term of the sequence 34, 37, 40, 43

The answer would be 127 the pattern is + 3

Increases by 3 each time

aritmetic sequence, firsrt term is 34, 3=common differnce

an=a1+d (n-1) is da formlua

a1=first term

d=common differnce

an=34+3 (n-1)

so 32n'd term is

a32=34+3 (32-1)

a32=34+3 (31)

a32=34+93

a32=127

the 32nd term is 127