If ƒ (x) = x^2 + 1, find ƒ (a + 1).

a^2 + 2

a^2+a+1

a^2+2a+2

I'm pretty sure that this is how it goes

If ƒ (x) = x^2 + 1, find ƒ (a + 1).

x = (a+1) so u replace x to get this:

f (a+1) = (a+1) ^2+1

If you square "a" it just becomes a^2 and "1" squared is just "1"

1+1=2

Answer: a^2+2a+2

The third option is the answer.